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Q.Find the eccentricity of the hyperbola 16x2−9y2=14416x^2-9y^2=144.

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Divide through by 144 to reach standard form, identify a2a^2 and b2b^2, then substitute into the hyperbola eccentricity formula (note the ++, unlike the ellipse's −-).

16x2−9y2=144 ⇒ x29−y216=116x^2-9y^2=144\ \Rightarrow\ \dfrac{x^2}{9}-\dfrac{y^2}{16}=1

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