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Q.Resolve x2−x+1(x+1)(x−1)2\dfrac{x^2 - x + 1}{(x + 1)(x - 1)^2} into partial fractions.

Yanam BieapBIEAP Intermediate Board 2022Subjective· 4mImportance★★★★★
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x2−x+1(x+1)(x−1)2=34(x+1)+14(x−1)+12(x−1)2.\dfrac{x^2-x+1}{(x+1)(x-1)^2}=\dfrac{3}{4(x+1)}+\dfrac{1}{4(x-1)}+\dfrac{1}{2(x-1)^2}.

Assume x2−x+1(x+1)(x−1)2=Ax+1+Bx−1+C(x−1)2.\dfrac{x^2-x+1}{(x+1)(x-1)^2}=\dfrac{A}{x+1}+\dfrac{B}{x-1}+\dfrac{C}{(x-1)^2}.

Multiply through: x2−x+1=A(x−1)2+B(x+1)(x−1)+C(x+1).x^2-x+1=A(x-1)^2+B(x+1)(x-1)+C(x+1).

Put x=1x=1:  1=C(2)⇒C=12.\ 1=C(2)\Rightarrow C=\tfrac12.

Put x=−1x=-1:  3=A(4)⇒A=34.\ 3=A(4)\Rightarrow A=\tfrac34. …

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