Additional Exercises · 13.28
Q.Consider the D-T reaction (deuterium-tritium fusion)
[!FORMULA]
(a) Calculate the energy released in MeV in this reaction from the data:
u
u
u
u
(b) Consider the radius of both deuterium and tritium to be approximately 2.0 fm. What is the kinetic energy needed to overcome the coulomb repulsion between the two nuclei? To what temperature must the gas be heated to initiate the reaction? (Hint: Kinetic energy required for one fusion event = average thermal kinetic energy available with the interacting particles = ; = Boltzmann's constant, = absolute temperature.)
Yanam BieapTextbookSubjective· 3mImportance★★★★★
64% · 32/50 Questions
You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.
Start your 14-day free trial to unlock the full solution →- Mass-defect calculation gives MeV for D-T fusion.
- The Coulomb barrier at 4 fm separation is MeV, and equating this to the average thermal kinetic energy gives an ignition temperature of K — illustrating why practical fusion needs enormous confined temperatures (real reactors get away with somewhat lower temperatures thanks to quantum tunneling and the high-energy tail of the thermal distribution, but the order of magnitude here is the right one).
- Energy released
Using u and u (given earlier in this chapter's data):
- Coulomb barrier and ignition temperature
At the moment the two nuclei just touch, the centre-to-centre separation is:
The Coulomb potential energy at this separation (both nuclei carry charge ): …
Unlock everything free for 14 days
- Full step-by-step solutions
- Concept-first explanations
- Methods, shortcuts & mistakes
- PYQ mapping + timed mock tests
Full access for 14 days. No credit card required.