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Worked Examples · Example 5

Q.A sum of money lent out at simple interest amounts to ₹2,200 in one year and ₹2,800 in 4 years. Find the sum of money and the rate of interest.

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The difference between the two amounts over 3 years gives the annual SI; work back to find the principal and rate.

Amount A=P+SIA=P+SI, and (since SI accrues uniformly) SI per year =A2−A1T2−T1=\dfrac{A_2-A_1}{T_2-T_1}; also SI=P×R×T100SI=\dfrac{P\times R\times T}{100}.

Given: A1=₹2,200A_1=₹2{,}200 at T1=1T_1=1 year; A2=₹2,800A_2=₹2{,}800 at T2=4T_2=4 years.

  1. Extra interest earned between year 1 and year 4 (i.e., over 3 years):

2800−2200=₹6002800-2200=₹600

  1. Annual SI =6004−1=6003=₹200=\dfrac{600}{4-1}=\dfrac{600}{3}=₹200 per year.
  2. Amount at end of year 1 == Principal ++ 1 year's SI: P+200=2200⇒P=₹2,000P+200=2200\Rightarrow P=₹2{,}000 …

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