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Exercise 1.3 · Q4

Q.Simplify: a=x3y4x5y2a = \dfrac{x^{3} y^{4}}{x^{5} y^{2}}.

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Each base's exponents are subtracted independently, then a negative exponent is rewritten as a reciprocal.

[!FORMULA]

xmxn=xm−n\dfrac{x^{m}}{x^{n}}=x^{m-n}; and x−k=1xkx^{-k}=\dfrac{1}{x^{k}}.

  1. Subtract exponents of xx: 3−5=−2⇒x−23-5=-2\Rightarrow x^{-2}.
  2. Subtract exponents of yy: 4−2=2⇒y24-2=2\Rightarrow y^{2}. …

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