Skip to content
Worked Examples · Example 4

Q.Express the following in factorial notation.

(i) 6×7×8×96 \times 7 \times 8 \times 9
(ii) 4×5×62×7×84 \times 5 \times 6^2 \times 7 \times 8
Yanam CbseNCERTSubjective· 2mImportance★★★★★est
10% · 13/126 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Write each product as a ratio (or a single) factorial by matching it to a run of consecutive integers.

A product of consecutive integers from (r+1)(r+1) to nn equals n!r!\dfrac{n!}{r!}, since n!=n×(n−1)×⋯×(r+1)×r!n! = n\times(n-1)\times\cdots\times(r+1)\times r!.

  1. (i) 6×7×8×96\times7\times8\times9 is the product of consecutive integers from 66 to 99. Taking n=9n=9 and r=5r=5: 9!5!=9×8×7×6×5!5!=9×8×7×6\dfrac{9!}{5!} = \dfrac{9\times8\times7\times6\times5!}{5!} = 9\times8\times7\times6, which matches. So 6×7×8×9=9!5!6\times7\times8\times9 = \dfrac{9!}{5!}.
  2. (ii) Rewrite 62=6×66^2 = 6\times6, so 4×5×62×7×8=4×5×6×6×7×84\times5\times6^2\times7\times8 = 4\times5\times6\times6\times7\times8.
  3. Group the consecutive run 4×5×6×7×8=8!3!=8×7×6×5×4=67204\times5\times6\times7\times8 = \dfrac{8!}{3!} = 8\times7\times6\times5\times4 = 6720 (using the same rule with n=8, r=3n=8,\ r=3). …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.