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Exercise 6.2 · Q4

Q.A tennis club consists of 8 boys and 11 girls. In how many ways can a mixed doubles team be chosen?

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Choosing 1 boy from 8 and 1 girl from 11 for a mixed-doubles pair gives 8×11=888\times11=88 ways.

[!FORMULA] nCr=n!r!(n−r)!^{n}C_{r}=\dfrac{n!}{r!(n-r)!} counts unordered selections of rr items from nn distinct items. By the multiplication principle, if a boy is chosen in 8C1^{8}C_1 ways and, independently, a girl in 11C1^{11}C_1 ways, the pair is chosen in 8C1×11C1^{8}C_1\times{}^{11}C_1 ways.

  1. A mixed doubles team needs exactly one boy and one girl, and within a category the order of choosing does not matter (it is a selection, not an arrangement), so combinations apply.

  2. Number of ways to choose 1 boy out of 8: 8C1=8^{8}C_1=8.

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