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Worked Examples · Example 6

Q.If (−1,1),(2,3),(1,0),(2,1)(-1, 1), (2, 3), (1, 0), (2, 1) are some of the elements of A×BA \times B, then find AA and BB. Also find the remaining elements of A×BA \times B.

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The distinct components give A={−1,1,2}A=\{-1,1,2\}, B={0,1,3}B=\{0,1,3\}; the full 3×3=93\times3=9-element product minus the 44 given pairs leaves 55 remaining elements.

For A×B={(a,b):a∈A, b∈B}A\times B=\{(a,b):a\in A,\ b\in B\}: AA = set of distinct first components appearing across all listed pairs of A×BA\times B; BB = set of distinct second components; and n(A×B)=n(A)×n(B)n(A\times B)=n(A)\times n(B) gives the total count, from which the "remaining" (unlisted) elements can be found.

  1. Given elements of A×BA\times B: (−1,1),(2,3),(1,0),(2,1)(-1,1),(2,3),(1,0),(2,1).

  2. Extract distinct first components → set AA.

{−1, 2, 1, 2} ⇒ A={−1,1,2}(n(A)=3)\{-1,\ 2,\ 1,\ 2\}\ \Rightarrow\ A=\{-1,1,2\}\quad(n(A)=3)

  1. Extract distinct second components → set BB.

{1, 3, 0, 1} ⇒ B={0,1,3}(n(B)=3)\{1,\ 3,\ 0,\ 1\}\ \Rightarrow\ B=\{0,1,3\}\quad(n(B)=3)

  1. Total size of A×BA\times B.

n(A×B)=n(A)×n(B)=3×3=9n(A\times B)=n(A)\times n(B)=3\times3=9

  1. List all 99 elements of A×B={−1,1,2}×{0,1,3}A\times B=\{-1,1,2\}\times\{0,1,3\} in order: …

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