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Worked Examples · Example 22

Q.In a class of 35 students, 17 have taken Mathematics, 10 have taken Mathematics but not Economics. If each student has taken either of the two subjects, then find the number of students who have taken Economics but not Mathematics.

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Find the overlap from "Maths total" minus "Maths only", then use the union formula (union = total, since every student takes at least one subject) to find Economics, then subtract the overlap.

Maths only =n(M)−n(M∩E)=n(M)-n(M\cap E); since every student takes at least one subject, n(M∪E)=Total students=n(M)+n(E)−n(M∩E)n(M\cup E)=\text{Total students}=n(M)+n(E)-n(M\cap E); Economics but not Maths =n(E)−n(M∩E)=n(E)-n(M\cap E).

  1. Given: total students =35=35, n(M)=17n(M)=17, Maths only =10=10. Every student takes at least one of the two subjects, so n(M∪E)=35n(M\cup E)=35.
  2. Find the overlap: n(M∩E)=n(M)−Maths only=17−10=7n(M\cap E)=n(M)-\text{Maths only}=17-10=7.
  3. Substitute into the union formula: 35=n(M)+n(E)−n(M∩E)=17+n(E)−735=n(M)+n(E)-n(M\cap E)=17+n(E)-7. …

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