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Worked Examples · Example 5.5

Q.Let us compute the standard deviation of the hight of nine students that we used while calculating Mean. The Mean (x̄) was calculated to be 101.33 cm.

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Standard deviation (σ) measures how far values typically sit from the mean. Recipe: subtract the mean from each value, square, average the squares (that is the variance), take the square root. For the nine heights (mean 101.33 cm) this gives σ = √(938/9) ≈ 10.21 cm.

Why squares?

Deviations from the mean always sum to (nearly) zero — positives cancel negatives — so averaging them directly tells us nothing. Squaring makes every deviation positive; taking the square root at the end returns the answer to the original unit (cm).

Step-by-step table

Mean x̄ = 912 / 9 = 101.33 cm (from the earlier example). For each height x, compute the deviation (x − x̄) and its square:

x (cm)x − x̄(x − x̄)²
90−11.33128.44
1020.670.44
1108.6775.11
11513.67186.78
85−16.33266.78
90−11.33128.44
100−1.331.78
1108.6775.11
1108.6775.11
Sum≈ 0938.00

(The deviation column summing to ~0 is a good self-check that the mean was right.)

Variance = 938 / 9 ≈ 104.22 cm²

Standard deviation σ = √104.22 ≈ 10.21 cm

Interpretation: heights typically differ from the class mean by about 10 cm — consistent with the data, where values run from 16.33 below the mean (85) to 13.67 above it (115).

In Python

import statistics

heights = [90, 102, 110, 115, 85, 90, 100, 110, 110]

mean = statistics.mean(heights)
sq_dev = [(x - mean) ** 2 for x in heights]
variance = sum(sq_dev) / len(heights)
sigma = variance ** 0.5 …

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