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Exercise 4.1 · Q1

Q.Express the following in the form a+iba + ib: 5i(−35i)5i\left(-\dfrac{3}{5}i\right)

Yanam CbseNCERTSubjective· 2mImportance★★★★★est
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✓ Free question

The product of two purely imaginary numbers is a real number. Here, 5i×(−35i)=35i \times \left(-\frac{3}{5}i\right) = 3, which is 3+0i3 + 0i.

Why This Works

When you multiply complex numbers, the key is to treat ii as −1\sqrt{-1} and follow the usual rules of algebra. The expression 5i(−35i)5i\left(-\frac{3}{5}i\right) is a product of two purely imaginary numbers — each has no real part. The trick is that i×i=i2=−1i \times i = i^2 = -1, so the product of two imaginary numbers always lands back on the real number line. That’s the core insight: you’re not dealing with anything mysterious, just a clean multiplication that collapses to a real result.

Step-by-Step

  1. Write the product clearly.

    We have 5i×(−35i)5i \times \left(-\frac{3}{5}i\right). The numbers are 5i5i and −35i-\frac{3}{5}i. Both are of the form 0+bi0 + bi, so they’re purely imaginary.

  2. Multiply the coefficients separately from the ii’s.

    Treat ii as an algebraic symbol:

5i×(−35i)=5×(−35)×i×i5i \times \left(-\frac{3}{5}i\right) = 5 \times \left(-\frac{3}{5}\right) \times i \times i

  1. Simplify the numerical part.

    5×(−35)=−35 \times \left(-\frac{3}{5}\right) = -3. So we have −3×(i×i)-3 \times (i \times i).

  2. Use the defining property of ii.

    i×i=i2=−1i \times i = i^2 = -1. Therefore:

−3×(−1)=3-3 \times (-1) = 3

  1. Write in a+iba + ib form. The result is 33, which is a real number. In the standard form a+iba + ib, this is 3+0i3 + 0i.
Watch out

A common mistake is to forget that i2=−1i^2 = -1 and instead treat i×ii \times i as i2i^2 without simplifying. Another pitfall is to leave the answer as 3i3i — but that would mean 3×i3 \times i, which is wrong. The product of two ii’s gives −1-1, not another ii.

Tip

Whenever you multiply two purely imaginary numbers, the result is always real. This is because (bi)(di)=bd⋅i2=−bd(bi)(di) = bd \cdot i^2 = -bd, a real number. So if you see a product like this, you can jump straight to the real answer.

✓Final answer

The expression simplifies to 33, which in a+iba + ib form is 3+0i\boxed{3 + 0i}.

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