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NCERT Exemplar · Q47

Q.The length of the longest piece of a string that can be stretched straight in a rectangular room whose dimensions are 10, 13 and 8 units are ______.

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The longest piece of string that can be stretched straight in a rectangular room is its space diagonal, calculated using the 3D Pythagorean theorem. The length is 337\boxed{3\sqrt{37}} units.

A rectangular room is a three-dimensional shape known as a cuboid. When we talk about stretching a string straight within this room, we are looking for the longest possible straight line segment that can fit entirely inside it.

Concept and Intuition: The Space Diagonal

Imagine you are standing in one corner of the room, say the bottom-front-left corner. If you want to stretch a string to the furthest possible point in a straight line, you would aim for the opposite corner – the top-back-right corner. This line segment, connecting two opposite vertices of the cuboid, is called the space diagonal. Any other line segment within the room (like an edge, a face diagonal, or a line connecting non-opposite points) will be shorter than or equal to this space diagonal.

The length of this space diagonal can be found by extending the familiar Pythagorean theorem into three dimensions. Just as a 2D diagonal in a rectangle with sides aa and bb is a2+b2\sqrt{a^2 + b^2}, a 3D diagonal in a cuboid with dimensions ll, ww, and hh is l2+w2+h2\sqrt{l^2 + w^2 + h^2}.

The length of the space diagonal DD of a cuboid with length ll, width ww, and height hh is given by:

D=l2+w2+h2D = \sqrt{l^2 + w^2 + h^2}

Let's apply this concept to the given dimensions.

  1. Identify the dimensions:

    The dimensions of the rectangular room are given as 10, 13, and 8 units. We can assign these to the length (ll), width (ww), and height (hh) in any order, as addition is commutative.

    Let l=10l = 10 units, w=13w = 13 units, and h=8h = 8 units.

  2. Apply the space diagonal formula: …

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