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Miscellaneous Exercise · Q5

Q.−12<4−3x−5≤2-12 < 4 - \dfrac{3x}{-5} \le 2

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This is a compound inequality with a negative denominator. The key is to multiply by the negative number −5-5 correctly, which reverses the inequality signs. After simplifying, the solution is x∈[103,803)x \in \left[ \frac{10}{3}, \frac{80}{3} \right).

The Concept: Linear Inequality Solutions

When you see a compound inequality like −12<4−3x−5≤2-12 < 4 - \frac{3x}{-5} \le 2, the instinct is to isolate xx in the middle. But there's a trap: the denominator is −5-5. Dividing by a negative flips inequality signs, and here we have to multiply by −5-5 to clear the fraction. That multiplication will reverse both inequality signs. Many students forget this and get the direction wrong.

The core idea: treat the compound inequality as two separate inequalities joined by "and". Solve each one, then take the intersection of their solution sets. But it's faster to work on the whole expression at once, as long as you're careful with sign flips.

Let's break it down.


  1. Rewrite the inequality clearly

    We have:

−12<4−3x−5≤2-12 < 4 - \frac{3x}{-5} \le 2

Notice 3x−5=−3x5\frac{3x}{-5} = -\frac{3x}{5}. So the middle term becomes:

4−(−3x5)=4+3x54 - \left(-\frac{3x}{5}\right) = 4 + \frac{3x}{5}

The inequality is now:

−12<4+3x5≤2-12 < 4 + \frac{3x}{5} \le 2

This is simpler — no negative denominator in sight.

  1. Isolate the term with xx

    Subtract 4 from all three parts:

−12−4<4+3x5−4≤2−4-12 - 4 < 4 + \frac{3x}{5} - 4 \le 2 - 4

−16<3x5≤−2-16 < \frac{3x}{5} \le -2

Now we have 3x5\frac{3x}{5} trapped between −16-16 and −2-2.

  1. Multiply through by 5 (positive, so no sign change)

    Multiply every part by 5:

−16×5<3x5×5≤−2×5-16 \times 5 < \frac{3x}{5} \times 5 \le -2 \times 5

−80<3x≤−10-80 < 3x \le -10

  1. Divide by 3 (positive, so no sign change)

    Divide all three parts by 3: …

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