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Exercise 1.2 · Q1

Q.Which of the following are examples of the null set

(i) Set of odd natural numbers divisible by 2
(ii) Set of even prime numbers
(iii) { x : x is a natural numbers, x < 5 and x > 7 }
(iv) { y : y is a point common to any two parallel lines}
Yanam CbseNCERTSubjective· 2mImportance★★★★★est
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✓ Free question

A null set is a set with no elements. Among the given options, (i), (iii), and (iv) are null sets because no element satisfies their defining conditions; (ii) is not null because 2 is an even prime number.

The idea of a null set (or empty set) is simple: it’s a set that contains nothing. But in exam problems, the trick is to check whether the description of the set actually allows any object to exist. You don’t guess — you test each condition logically.

Let’s go through each option one by one.


1. Option (i): Set of odd natural numbers divisible by 2

A natural number that is odd cannot be divisible by 2 — divisibility by 2 is the very definition of being even. So the condition “odd and divisible by 2” is impossible. No natural number satisfies both.

Therefore, this set has no elements — it is a null set.

Watch out

A common mistake is to think “0 is odd and divisible by 2” — but 0 is not a natural number in most Indian exam contexts (natural numbers start from 1). Even if it were, 0 is even, not odd. So the set remains empty.


2. Option (ii): Set of even prime numbers

A prime number has exactly two distinct positive divisors: 1 and itself. The number 2 is prime, and it is also even (the only even prime). So 2 belongs to this set.

Since there is at least one element, this set is not a null set.

Tip

Memorise: 2 is the only even prime. This fact often appears in multiple-choice questions about prime numbers or null sets.


3. Option (iii): {x:x is a natural number,x<5 and x>7}\{ x : x \text{ is a natural number}, x < 5 \text{ and } x > 7 \}

The condition says x<5x < 5 and x>7x > 7 simultaneously. No real number can be both less than 5 and greater than 7 — the two inequalities have no overlap. Since natural numbers are a subset of real numbers, no natural number satisfies both.

Hence, this set is a null set.


4. Option (iv): {y:y is a point common to any two parallel lines}\{ y : y \text{ is a point common to any two parallel lines} \}

Parallel lines, by definition, never intersect. They have no common point. So the set of points common to two parallel lines is empty.

Thus, this is a null set.


✓Final answer

The null sets are (i), (iii), and (iv).

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