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Exercise 9.1 · Q9

Q.Find the angle between the x-axis and the line joining the points (3,−1)(3, -1) and (4,−2)(4, -2).

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The angle a line makes with the positive xx-axis is given by θ=tan⁡−1(m)\theta = \tan^{-1}(m), where mm is the slope. For the points (3,−1)(3, -1) and (4,−2)(4, -2), the slope is −1-1, giving an angle of 135°135° (or 3π4\frac{3\pi}{4} radians).

Understanding the Angle with the xx-axis

When we talk about the angle a line makes with the xx-axis, we mean the angle measured counter-clockwise from the positive xx-axis to the line. This angle is intrinsically connected to the line's slope through the tangent function: if a line has slope mm, then m=tan⁡θm = \tan\theta, where θ\theta is this angle.

The reason is geometric. Slope measures "rise over run" — the vertical change per unit horizontal change. When you move one unit along the xx-axis and rise by mm units, you've traced out a right triangle whose opposite side is mm and adjacent side is 11. The angle at the origin is precisely θ\theta, and tan⁡θ=m1=m\tan\theta = \frac{m}{1} = m.

Solution

  1. Calculate the slope of the line joining (3,−1)(3, -1) and (4,−2)(4, -2).

    The slope formula for two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is:

m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1}

Substituting our points:

m=−2−(−1)4−3=−2+11=−11=−1m = \frac{-2 - (-1)}{4 - 3} = \frac{-2 + 1}{1} = \frac{-1}{1} = -1

  1. Find the angle using the inverse tangent.

    Since m=tan⁡θm = \tan\theta, we have:

tan⁡θ=−1\tan\theta = -1

The principal value of tan⁡−1(−1)\tan^{-1}(-1) is −45°-45° or −π4-\frac{\pi}{4} radians. However, this gives us an angle measured clockwise from the positive xx-axis (a negative angle).

  1. Interpret the angle correctly. …

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