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Exercise 9.2 · Q5

Q.Intersecting the x-axis at a distance of 33 units to the left of origin with slope −2-2.

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The key idea is that a line’s equation can be found using a point on it and its slope. Here the line passes through (−3,0)(-3,0) with slope −2-2, so the equation is y=−2x−6y = -2x - 6.

Why This Works

When you’re told a line “intersects the x-axis at a distance of 3 units to the left of origin”, that’s a precise way of giving you a point: the x-intercept. The x-axis is where y=0y = 0, and “3 units to the left” means the x-coordinate is −3-3. So the line passes through (−3,0)(-3, 0).

The slope is given directly as −2-2. With a point and a slope, the most natural tool is the point-slope form of a line:

y−y1=m(x−x1)y - y_1 = m(x - x_1)

where (x1,y1)(x_1, y_1) is a known point and mm is the slope. This formula comes straight from the definition of slope: m=y−y1x−x1m = \frac{y - y_1}{x - x_1}, rearranged.

Step-by-Step Solution

  1. Identify the point.

    The x-intercept is (−3,0)(-3, 0). So x1=−3x_1 = -3, y1=0y_1 = 0.

  2. Identify the slope.

    m=−2m = -2.

  3. Plug into point-slope form.

y−0=−2 (x−(−3))y - 0 = -2\,(x - (-3))

Simplify the double negative:

y=−2 (x+3)y = -2\,(x + 3)

  1. Distribute to get slope-intercept form. y=−2x−6y = -2x - 6 …

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