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NCERT Exemplar · Q2

Q.One mole of an ideal gas at 300 K is contained in a cubical vessel of volume VV whose eight corners are labelled A, B, C, D, E, F, G, H, so that ABCD and EFGH are two opposite (parallel) faces of the cube. The face EFGH is made of a material that totally absorbs every gas molecule that strikes it (the molecules are not reflected back), while the opposite face ABCD reflects molecules in the usual way. At any given instant, which statement about the pressure on the faces is correct?

(a) the pressure on EFGH would be zero.
(b) the pressure on all the faces will be equal.
(c) the pressure on EFGH would be double the pressure on ABCD.
(d) the pressure on EFGH would be half that on ABCD.
Yanam CbseMCQ· 1mImportance★★★★★est
42% · 21/50 Questions
✓ Free question

The pressure on a wall equals the rate at which molecules deliver momentum to it. An ordinary reflecting wall receives 2mv2mv from each normal hit, but the absorbing face EFGH receives only mvmv per hit (the molecule is captured, it does not rebound). Hence EFGH experiences half the pressure of the opposite reflecting face ABCD.

Concept

Gas pressure is the average force per unit area that molecules exert on a wall, and this force is the rate of momentum transfer per unit area during collisions.

Why this formula

For a molecule whose velocity component normal to the wall has magnitude vv:

  • Striking a normal (reflecting) wall it bounces straight back, so its momentum changes by

Δpreflect=mv−(−mv)=2mv.\Delta p_{\text{reflect}} = mv - (-mv) = 2mv.

  • Striking the absorbing face EFGH it sticks and does not return, so

Δpabsorb=mv−0=mv.\Delta p_{\text{absorb}} = mv - 0 = mv.

Steps

  1. At any instant the same flux of molecules (same number density and speed distribution) strikes both opposite faces.
  2. Each strike on ABCD transfers 2mv2mv; each strike on EFGH transfers mvmv.
  3. Pressure is proportional to the momentum delivered per collision, so

pEFGH=12 pABCD.p_{EFGH} = \tfrac12\, p_{ABCD}.

Why the distractors fail

  • (A) is wrong: absorbed molecules still deliver momentum mvmv, so the pressure is not zero.
  • (B) is wrong: a reflecting face and an absorbing face cannot feel the same pressure.
  • (C) is wrong: absorption halves, not doubles, the momentum transfer.
✓Final answer

(D) The pressure on EFGH would be half that on ABCD.

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