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Exercise 3 · Q5

Q.Find the differential equation representing the parabolas having their vertices at origin and foci on positive direction of x-axis.

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Vertex at origin with focus on the positive xx-axis means y2=4axy^2=4ax; one differentiation eliminates aa to give 2xdydx=y2x\dfrac{dy}{dx}=y.

Parabola, vertex origin, focus on positive xx-axis: y2=4axy^2=4ax, a>0a>0 = one arbitrary constant (order 1).

Steps

  1. Standard equation of the family:

y2=4ax.(1)y^2=4ax.\qquad(1)

  1. Differentiate with respect to xx: 2ydydx=4a  ⇒  4a=2ydydx.(2)2y\frac{dy}{dx}=4a\;\Rightarrow\;4a=2y\frac{dy}{dx}.\qquad(2) …

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