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Worked Examples · Example 13

Q.A couple wishes to purchase a house for ₹10,00,000 with a down payment of ₹2,00,000. If they can amortize the balance at 9% per annum compounded monthly for 25 years, what is their monthly payment? What is the total interest paid? (Given a300‾∣0.0075=119.1616a_{\overline{300}|0.0075} = 119.1616)

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The couple borrows 10,00,000−2,00,000=₹8,00,00010{,}00{,}000-2{,}00{,}000=₹8{,}00{,}000 at 9% p.a. compounded monthly for 25 years. Using the given annuity factor, the monthly payment is R=8,00,000119.1616=₹6,713.57R=\dfrac{8{,}00{,}000}{119.1616}=₹6{,}713.57 and the total interest is ₹12,14,071₹12{,}14{,}071.

The loan is the present value of all the future monthly payments, discounted at the monthly rate. With payments equal and regular, this is an ordinary annuity.

  1. Loan principal. P=10,00,000−2,00,000=₹8,00,000P=10{,}00{,}000-2{,}00{,}000=₹8{,}00{,}000.
  2. Monthly rate and number of payments. i=0.0912=0.0075i=\dfrac{0.09}{12}=0.0075, n=25×12=300n=25\times12=300. …

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