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Worked Examples · Example 6

Q.A company establishes sinking fund to provide for the payment of ₹1,00,000 debt maturing in 4 years. Contributions to the fund are to be made at the end of every year. Find the amount of each annual deposit if interest is 18% per annum.

Yanam CbseNCERTSubjective· 3mImportance★★★★★
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✓ Free question

The equal end-of-year deposits form an ordinary annuity whose future value must equal ₹1,00,000 in 4 years at 18%. Each deposit is R=1,00,0005.2156≈₹19,173.25R=\dfrac{1{,}00{,}000}{5.2156}\approx ₹19{,}173.25.

A sinking fund accumulates equal end-of-year deposits RR that earn compound interest. The future value of the annuity must reach ₹1,00,000 in 4 years at 18% per annum.

F=R[(1+i)n−1i]F=R\left[\frac{(1+i)^n-1}{i}\right]

  1. Set up the equation with F=1,00,000F=1{,}00{,}000, i=0.18i=0.18, n=4n=4:

1,00,000=R[(1.18)4−10.18].1{,}00{,}000=R\left[\frac{(1.18)^4-1}{0.18}\right].

  1. Evaluate the accumulation factor. (1.18)4=1.9388(1.18)^4=1.9388, so

1.9388−10.18=0.93880.18=5.2156.\frac{1.9388-1}{0.18}=\frac{0.9388}{0.18}=5.2156.

  1. Solve for RR.

R=1,00,0005.2156≈₹19,173.25.R=\frac{1{,}00{,}000}{5.2156}\approx ₹19{,}173.25.

✓Final answer

Each annual deposit is R=1,00,0005.2156≈₹19,173.25R=\dfrac{1{,}00{,}000}{5.2156}\approx \mathbf{₹19{,}173.25}.

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