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Practice Exercise · Q6
Q.

Based on the data on the expenses of middle-class families in a certain city, calculate the cost-of-living index during the year 2003 as compared with 1990:

ExpensesYearFoodFuelClothingRentMiscellaneous
Price (in ₹)20031500250750300425
Price (in ₹)19901400200400200250
Yanam CbseNCERTSubjective· 3mImportance★★★★★est
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Taking 1990 as base, the total expenses rise from ₹2450₹2450 to ₹3225₹3225, giving a cost-of-living index =32252450×100=131.63=\dfrac{3225}{2450}\times100=131.63.

Cost-of-living index=∑p1∑p0×100\text{Cost-of-living index}=\dfrac{\sum p_1}{\sum p_0}\times100

where ∑p0\sum p_0 = total base-year (1990) expenses and ∑p1\sum p_1 = total current-year (2003) expenses.

Working table

HeadExpense 1990 (p0)(p_0) (₹)Expense 2003 (p1)(p_1) (₹)
Food14001500
Fuel200250
Clothing400750
Rent200300
Miscellaneous250425
Total24503225
  1. ∑p0=1400+200+400+200+250=₹2450\sum p_0 = 1400+200+400+200+250 = ₹2450.
  2. ∑p1=1500+250+750+300+425=₹3225\sum p_1 = 1500+250+750+300+425 = ₹3225. …

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