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Check Your Progress · Q8

Q.A pair of dice is thrown and the random variable X represents the sum of the numbers that appear on the two dice. Calculate the mathematical expectation of X.

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Building the probability distribution of the sum XX (values 22 to 1212 over 3636 equally-likely outcomes) and applying E(X)=∑xP(X=x)E(X)=\sum xP(X=x) gives E(X)=7E(X)=7.

E(X)=∑xx P(X=x)E(X)=\sum_{x} x\,P(X=x)

where XX is the random variable (sum of the two faces) and P(X=x)P(X=x) is the probability of that sum. Total outcomes =6×6=36=6\times6=36.

Steps

  1. List the number of ways each sum occurs and its probability:
xx (sum)WaysP(X=x)P(X=x)
211/361/36
322/362/36
433/363/36
544/364/36
655/365/36
766/366/36
855/365/36
944/364/36
1033/363/36
1122/362/36
1211/361/36
  1. Check the probabilities sum to 11: 1+2+3+4+5+6+5+4+3+2+136=3636=1.\dfrac{1+2+3+4+5+6+5+4+3+2+1}{36}=\dfrac{36}{36}=1.

  2. Compute ∑xP(X=x)\sum xP(X=x): …

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