Worked Examples · Example 13
Q.Discuss the continuity of the function given by .
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Start your 14-day free trial to unlock the full solution →At the two one-sided limits and all equal , so is continuous there; each piece is a polynomial, so is continuous on all of .
Where to look
Continuity at needs defined, to exist, and the two to be equal. The pieces and are polynomials, continuous on their own, so only the join at needs checking.
Value at the point
Since , the top rule applies: .
One-sided limits
From the left (, ):
From the right (, ):
Compare
Both one-sided limits are , so , and this equals . All three continuity conditions hold at .
Watch out
Two different formulas ( vs ) do not force a jump. Compute the limits — here both sides meet at , so there is no break. …
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