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Mathematics · Ch 9 — Differential Equations

Differential Equations with Variables Separable

9.4.1

Differential Equations with Variables Separable

9.4.1 Differential Equations with Variables Separable

The Core Idea: When a Derivative Factorises

A first-order, first-degree differential equation has the general form

dydx=F(x,y)\frac{dy}{dx} = F(x, y)

The difficulty of solving it depends on the structure of F(x,y)F(x, y). The simplest case — treated first — occurs when F(x,y)F(x, y) factorises into a function of xx alone times a function of yy alone.

Note

"Variables separable" means exactly what it says: the two variables can be separated to opposite sides of the equation, each with its own differential.

If F(x,y)=g(x)⋅h(y)F(x, y) = g(x) \cdot h(y), the differential equation becomes

dydx=h(y)⋅g(x)⋯(2)\frac{dy}{dx} = h(y) \cdot g(x) \qquad \cdots (2)

a variable separable differential equation.

The Separation Procedure

Provided h(y)≠0h(y) \neq 0, treat dydy and dxdx as algebraic quantities (Leibniz's notation) and separate the variables:

1h(y) dy=g(x) dx⋯(3)\frac{1}{h(y)} \, dy = g(x) \, dx \qquad \cdots (3)

Now integrate both sides:

∫1h(y) dy=∫g(x) dx⋯(4)\int \frac{1}{h(y)} \, dy = \int g(x) \, dx \qquad \cdots (4)

Writing H(y)H(y) for an antiderivative of 1h(y)\frac{1}{h(y)} and G(x)G(x) for one of g(x)g(x), equation (4) yields

H(y)=G(x)+CH(y) = G(x) + C

where CC is an arbitrary constant of integration. This is the general solution — a whole family of curves, one for each value of CC. …