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Exercise 9.2 · Q12

Q.The number of arbitrary constants in the particular solution of a differential equation of third order are: (A) 3 (B) 2 (C) 1 (D) 0

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The particular solution of a differential equation has zero arbitrary constants — all constants are eliminated when initial or boundary conditions are applied to the general solution. The correct answer is (D) 0.

Why the answer is zero — the core idea

The confusion here usually comes from mixing up the general solution with the particular solution. A third-order differential equation has a general solution containing three arbitrary constants (because you need to integrate three times). But the question asks about the particular solution — that’s a completely different beast.

A particular solution is obtained by plugging specific initial or boundary conditions into the general solution, which fixes every constant to a definite number. Once those constants become numbers, they are no longer “arbitrary.” So the count drops to zero.

Let’s walk through it step by step.


  1. General solution of a third-order DE A third-order differential equation involves the third derivative. Solving it requires three integrations, each introducing one arbitrary constant. So the general solution looks like:

y=f(x,C1,C2,C3)y = f(x, C_1, C_2, C_3)

where C1,C2,C3C_1, C_2, C_3 are arbitrary constants. That’s three constants — but this is not the particular solution.

  1. What makes a solution “particular”?

    To get a particular solution, you need extra information — typically three initial conditions (like y(x0)=ay(x_0)=a, y′(x0)=by'(x_0)=b, y′′(x0)=cy''(x_0)=c) or boundary conditions. You substitute these into the general solution (and its derivatives) to solve for C1,C2,C3C_1, C_2, C_3.

  2. Constants become fixed numbers

    After applying the conditions, each constant takes a specific numerical value. For example, you might get C1=5C_1 = 5, C2=−2C_2 = -2, C3=0C_3 = 0. These are no longer “arbitrary” — they are determined uniquely by the problem. …

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