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Exercise 7.1 · Q12

Q.Integrate the following function: ∫x3+3x+4xdx\int \frac{x^3 + 3x + 4}{\sqrt{x}} dx

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We rewrite the integrand as a sum of power functions by dividing each term by x=x1/2\sqrt{x} = x^{1/2}, then integrate term‑by‑term using the Power Rule. The result is 27x7/2+2x3/2+8x1/2+C\frac{2}{7}x^{7/2} + 2x^{3/2} + 8x^{1/2} + C.

The key to integrating a rational expression like this is to avoid trying to integrate the fraction as a whole. Instead, break it into separate fractions — one for each term in the numerator — and simplify each using the laws of exponents. Once every term is a simple power of xx, the Power Rule for integration does all the work.


Why the Power Rule works here

The Power Rule says: for any real number n≠−1n \neq -1,

∫xn dx=xn+1n+1+C.\int x^n \, dx = \frac{x^{n+1}}{n+1} + C.

Our integrand x3+3x+4x\frac{x^3 + 3x + 4}{\sqrt{x}} is not yet in the form xnx^n, but we can rewrite it. Since x=x1/2\sqrt{x} = x^{1/2}, dividing each term in the numerator by x1/2x^{1/2} gives a sum of terms like xsomethingx^{\text{something}}. Then we apply the Power Rule to each term separately.

Watch out

A common mistake is to try to integrate the numerator and denominator separately, e.g. ∫(x3+3x+4)∫x\frac{\int (x^3+3x+4)}{\int \sqrt{x}}. That is not valid — you cannot split an integral of a quotient into a quotient of integrals.


Step‑by‑step solution

1. Rewrite the square root as a power.

x3+3x+4x=x3+3x+4x1/2\frac{x^3 + 3x + 4}{\sqrt{x}} = \frac{x^3 + 3x + 4}{x^{1/2}}

2. Split into separate fractions and simplify each using xa/xb=xa−bx^a / x^b = x^{a-b}.

x3x1/2+3xx1/2+4x1/2=x3−1/2+3x1−1/2+4x−1/2=x5/2+3x1/2+4x−1/2\frac{x^3}{x^{1/2}} + \frac{3x}{x^{1/2}} + \frac{4}{x^{1/2}} = x^{3 - 1/2} + 3x^{1 - 1/2} + 4x^{-1/2} = x^{5/2} + 3x^{1/2} + 4x^{-1/2}

Now the integrand is a clean sum of power functions.

3. Integrate term by term using the Power Rule.

  • For x5/2x^{5/2}: n=52n = \frac{5}{2}, so n+1=72n+1 = \frac{7}{2}.

∫x5/2 dx=x7/27/2=27x7/2\int x^{5/2} \, dx = \frac{x^{7/2}}{7/2} = \frac{2}{7}x^{7/2}

  • For 3x1/23x^{1/2}: n=12n = \frac{1}{2}, so n+1=32n+1 = \frac{3}{2}.

∫3x1/2 dx=3⋅x3/23/2=3⋅23x3/2=2x3/2\int 3x^{1/2} \, dx = 3 \cdot \frac{x^{3/2}}{3/2} = 3 \cdot \frac{2}{3}x^{3/2} = 2x^{3/2}

  • For 4x−1/24x^{-1/2}: n=−12n = -\frac{1}{2}, so n+1=12n+1 = \frac{1}{2}. …

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