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NCERT Exemplar · Q2

Q.In the matrix A=[a1x23x2−y05−25]A = \begin{bmatrix} a & 1 & x \\ 2 & \sqrt{3} & x^2 - y \\ 0 & 5 & -\frac{2}{5} \end{bmatrix}, write:

(i) The order of the matrix AA
(ii) The number of elements
(iii) Write elements a23, a31, a12a_{23},\ a_{31},\ a_{12}.
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✓ Free question

A matrix is defined by its rows and columns. For matrix AA, the order is 3×33 \times 3, it has 99 elements, and the specific entries are a23=x2−ya_{23} = x^2 - y, a31=0a_{31} = 0, and a12=1a_{12} = 1.

Why Matrix Notation Matters

Every matrix is a rectangular array of numbers arranged in rows and columns. The notation aija_{ij} is the standard way to refer to the element in the ii-th row and jj-th column. Once you understand this indexing system, questions like this become simple lookup exercises — no calculation needed, just careful reading.

The matrix given is:

A=[a1x23x2−y05−25]A = \begin{bmatrix} a & 1 & x \\ 2 & \sqrt{3} & x^2 - y \\ 0 & 5 & -\frac{2}{5} \end{bmatrix}

Let’s walk through each part.


1. The order of the matrix

The order of a matrix is written as m×nm \times n, where mm is the number of rows and nn is the number of columns.

Count the rows: there are 3 horizontal lines of entries.

Count the columns: there are 3 vertical stacks of entries.

So the order is 3×33 \times 3.

Tip

Order is always "rows × columns". A common mistake is to reverse them — remember: Rows first, then Columns (alphabetical order helps: R before C).


2. The number of elements

The total number of elements in a matrix of order m×nm \times n is simply m×nm \times n.

Here, m=3m = 3 and n=3n = 3, so:

Number of elements=3×3=9\text{Number of elements} = 3 \times 3 = 9

You can also verify by counting the entries in the matrix: there are 9 numbers (including the variables aa, xx, yy).

Watch out

Don't confuse "number of elements" with "order". Order is 3×33 \times 3, but the number of elements is 99. They are related but not the same thing.


3. Writing the specific elements a23a_{23}, a31a_{31}, a12a_{12}

The notation aija_{ij} means: go to row ii, column jj, and read the entry there.

  • a23a_{23}: row 2, column 3.

    Row 2 is: [23x2−y][2 \quad \sqrt{3} \quad x^2 - y].

    Column 3 of that row is x2−yx^2 - y.

    So a23=x2−ya_{23} = x^2 - y.

  • a31a_{31}: row 3, column 1.

    Row 3 is: [05−25][0 \quad 5 \quad -\frac{2}{5}].

    Column 1 of that row is 00.

    So a31=0a_{31} = 0.

  • a12a_{12}: row 1, column 2.

    Row 1 is: [a1x][a \quad 1 \quad x].

    Column 2 of that row is 11.

    So a12=1a_{12} = 1.

Note

The entries aa, xx, yy are variables, not numbers — that's fine. The matrix is still well-defined; we just treat them as placeholders.


✓Final answer

The order is 3×33 \times 3, the number of elements is 99, and the required entries are a23=x2−ya_{23} = x^2 - y, a31=0a_{31} = 0, a12=1a_{12} = 1.

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