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Physics · Ch 8 — Electromagnetic Waves

Displacement Current

8.2

Displacement Current

The Problem with Ampere's Law

Ampere's circuital law (from Chapter 4) states that the line integral of the magnetic field B\mathbf{B} around a closed loop is proportional to the current passing through any surface bounded by that loop:

∮B⋅dl=μ0i(t)\oint \mathbf{B} \cdot d\mathbf{l} = \mu_0 i(t)

where μ0\mu_0 is the permeability of free space and i(t)i(t) is the current through the surface.

Consider a charging capacitor in a circuit with a time-dependent current i(t)i(t). To find the magnetic field at a point PP outside the capacitor, we take a circular loop of radius rr centered on the wire. By symmetry, the magnetic field is tangential and constant in magnitude on this loop, so:

B(2πr)=μ0i(t)B (2\pi r) = \mu_0 i(t)

Now, consider a different surface with the same boundary (the same circular loop) — a pot-shaped surface that passes between the capacitor plates, never touching the wire. No conduction current passes through this surface. Applying Ampere's law to this surface gives:

∮B⋅dl=0\oint \mathbf{B} \cdot d\mathbf{l} = 0

This is a contradiction: the same loop gives two different values for the magnetic field at PP. Ampere's law must be missing a term.

The Missing Term: Displacement Current

What passes through the surface between the capacitor plates? The electric field!

For a parallel plate capacitor with plate area AA and charge QQ, the electric field between the plates is:

E=Qε0AE = \frac{Q}{\varepsilon_0 A}

The electric flux through the surface SS (the flat bottom of the tiffin-shaped surface between the plates) is:

ΦE=∮E⋅dA=EA=Qε0\Phi_E = \oint \mathbf{E} \cdot d\mathbf{A} = EA = \frac{Q}{\varepsilon_0}

If the charge QQ changes with time, the current is i=dQdti = \frac{dQ}{dt}. Differentiating the flux equation:

dΦEdt=1ε0dQdt=iε0\frac{d\Phi_E}{dt} = \frac{1}{\varepsilon_0} \frac{dQ}{dt} = \frac{i}{\varepsilon_0}

Rearranging:

ε0dΦEdt=i\varepsilon_0 \frac{d\Phi_E}{dt} = i

This quantity ε0dΦEdt\varepsilon_0 \frac{d\Phi_E}{dt} has the same value as the conduction current ii and must be added to Ampere's law to resolve the contradiction.

Definition of Displacement Current

  • Conduction current (ici_c): current due to flow of charges in conductors.
  • Displacement current (idi_d): current due to changing electric field, defined as:

id=ε0dΦEdti_d = \varepsilon_0 \frac{d\Phi_E}{dt}

The total current is the sum:

i=ic+id=ic+ε0dΦEdti = i_c + i_d = i_c + \varepsilon_0 \frac{d\Phi_E}{dt}

The Ampere-Maxwell Law

The corrected, generalised form of Ampere's circuital law is:

∮B⋅dl=μ0ic+μ0ε0dΦEdt\oint \mathbf{B} \cdot d\mathbf{l} = \mu_0 i_c + \mu_0 \varepsilon_0 \frac{d\Phi_E}{dt}

This is called the Ampere-Maxwell law. It states that the source of a magnetic field is both conduction current and the time rate of change of electric field.

Physical Interpretation

  • Outside the capacitor plates: only conduction current ic=ii_c = i, displacement current id=0i_d = 0. …
Figure 8.1A parallel plate capacitor C, as part of a circuit through which a time dependent current i (t) flows, (a) a loop of radius r, to determine magnetic field at a point P on the loop; (b) a pot-shaped surface passing through the interior between the capacitor plates with the loop shown in (a) as its rim; (c) a tiffin-shaped surface with the circular loop as its rim and a flat circular bottom S between the capacitor plates. The arrows show uniform electric field between the capacitor plates.
Fig. 8.1 — A parallel plate capacitor C, as part of a circuit through which a time dependent current i (t) flows, (a) a loop of radius r, to determine magnetic field at a point P on the loop; (b) a pot-shaped surface passing through the interior between the capacitor plates with the loop shown in (a) as its rim; (c) a tiffin-shaped surface with the circular loop as its rim and a flat circular bottom S between the capacitor plates. The arrows show uniform electric field between the capacitor plates.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your NCERT textbook's own diagram.

What the Figure Shows

The figure has three panels, (a), (b), and (c), each showing the same parallel-plate capacitor C — two vertical plates, the left one with a column of + charges, the right with − charges. Short horizontal arrows between the plates indicate a uniform electric field pointing left to right. A horizontal wire enters from the left, carrying a time-dependent current i(t)i(t) (shown by an arrow). A point P is marked at the top-left of the plate gap, and a point M just inside the gap.

  • Panel (a): A thin vertical ellipse (the Amperian loop) of radius rr encircles the wire near the plates. Point P lies on this loop. The loop is perpendicular to the wire and centered on it.
  • Panel (b): The same loop now forms the mouth of a pot-shaped closed surface that bulges outward and dips its bottom between the capacitor plates, without touching the wire.
  • Panel (c): The loop is the rim of a tiffin-box-shaped surface (flat-bottomed). Its flat circular bottom S lies between the capacitor plates, perpendicular to the electric field. The label S marks this flat bottom.

The Physical Idea

The figure illustrates a contradiction that arises when applying Ampere’s circuital law to a charging capacitor. The law states:

∮B⋅dl=μ0i(t)\oint \mathbf{B} \cdot d\mathbf{l} = \mu_0 i(t)

where i(t)i(t) is the conduction current through the surface bounded by the loop.

  • In panel (a), the surface is the circular loop itself. The conduction current i(t)i(t) passes through it, so the law gives a nonzero magnetic field at P.
  • In panels (b) and (c), the same loop is the rim of different surfaces. Neither surface is pierced by the conduction current (the wire does not go through them). Applying Ampere’s law to these surfaces would give zero magnetic field at P — a contradiction.

Maxwell resolved this by proposing that a changing electric field also produces a magnetic field. The missing term is the displacement current:

id=ε0dΦEdti_d = \varepsilon_0 \frac{d\Phi_E}{dt}

where ΦE\Phi_E is the electric flux through the surface. For the flat bottom S in panel (c), the electric field between the plates is uniform and perpendicular to S, so the flux is:

ΦE=E⋅A=Qε0\Phi_E = E \cdot A = \frac{Q}{\varepsilon_0}

Thus, ε0dΦEdt=dQdt=i(t)\varepsilon_0 \frac{d\Phi_E}{dt} = \frac{dQ}{dt} = i(t), exactly the conduction current. Adding this term makes the total current the same for any surface bounded by the loop, removing the contradiction.

Key Formula Developed

The generalised Ampere-Maxwell law is:

∮B⋅dl=μ0(ic+ε0dΦEdt)\oint \mathbf{B} \cdot d\mathbf{l} = \mu_0 \left( i_c + \varepsilon_0 \frac{d\Phi_E}{dt} \right) …

Figure 8.2(a) The electric and magnetic fields E and B between the capacitor plates, at the point M. (b) A cross sectional view of Fig. (a).
Fig. 8.2 — (a) The electric and magnetic fields E and B between the capacitor plates, at the point M. (b) A cross sectional view of Fig. (a).

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your NCERT textbook's own diagram.

Figure 8.2 is a two‑panel diagram that shows the electric and magnetic fields inside a charging parallel‑plate capacitor. It is the key visual for understanding how a changing electric field acts as a source of magnetic field — the core idea of displacement current.


Panel (a) – Side view

  • The capacitor has two parallel plates: the left plate carries positive charges (++), the right plate negative charges (−-).
  • A time‑varying conduction current i(t)i(t) enters from the left, so the charge on the plates is increasing with time.
  • Point P is located just outside the capacitor (on the wire side), and point M is inside the gap between the plates.
  • Between the plates, the electric field E\mathbf{E} is drawn as a bold horizontal arrow pointing to the right — from the positive plate toward the negative plate. This field is uniform in the region between the plates (neglecting edge effects).
  • At point M, a short vector B\mathbf{B} is shown perpendicular to E\mathbf{E}. This magnetic field is circular around the axis of the capacitor (into/out of the page in this side view). The diagram emphasises that even though there is no conduction current inside the gap, a magnetic field exists there — it is produced by the changing electric field.

Panel (b) – Cross‑sectional (end‑on) view

  • This is a view looking along the axis of the capacitor, from the left plate toward the right plate.
  • The electric field E\mathbf{E} is represented by a disc filled with ×\times symbols — meaning E\mathbf{E} points into the page (away from the viewer). A radial arrow of length rr is labelled E\mathbf{E}, showing that the field is uniform across the disc.
  • The magnetic field B\mathbf{B} is drawn as circular arrows that are tangent to concentric dotted circles of radii rr and RR (labelled rr, RR). The arrows indicate that B\mathbf{B} circulates around the axis — it has no radial component.
  • Bold B\mathbf{B} labels are placed at several points on the circles, confirming that the magnitude of B\mathbf{B} is constant on a given circle but varies with radius.

Physical idea

The figure teaches that a time‑varying electric field produces a magnetic field, just as a conduction current does. Inside the capacitor, there is no moving charge (conduction current ic=0i_c = 0), yet a magnetic field is measured at point M. This magnetic field arises from the displacement current

id=ε0dΦEdt,i_d = \varepsilon_0 \frac{d\Phi_E}{dt},

where ΦE\Phi_E is the electric flux through a surface between the plates. The total current that acts as a source of B\mathbf{B} is

itotal=ic+id.i_{\text{total}} = i_c + i_d.


Key formula developed with this figure

The Ampere‑Maxwell law (generalised Ampere’s law) is

∮B⋅dl=μ0(ic+ε0dΦEdt).\oint \mathbf{B} \cdot d\mathbf{l} = \mu_0 \left( i_c + \varepsilon_0 \frac{d\Phi_E}{dt} \right).

  • ∮B⋅dl\oint \mathbf{B} \cdot d\mathbf{l}: line integral of magnetic field around a closed loop.
  • μ0\mu_0: permeability of free space (4π×10−7 T⋅m/A4\pi \times 10^{-7} \, \text{T·m/A}). …