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Worked Examples · Example 8

Q.The interval of real numbers between −3-3 and 22 (excluding both end points) is written as the open interval (−3,2)={x:x∈R,−3<x<2}(-3, 2) = \{x : x \in R, -3 < x < 2\}. Represent this as a segment of the real number line.

Andaman Nicobar CbseNCERTSubjective· 2mImportance★★★★★est
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✓ Free question

An open interval (−3,2)(-3,2) excludes both endpoints, so on the number line both boundary points are marked as open (unfilled) circles.

(a,b)={x∈R:a<x<b}(a,b)=\{x\in\mathbb{R}: a<x<b\} — open interval, both endpoints excluded, represented by open (hollow) circles at aa and bb joined by a solid line for the interior.

  1. Here a=−3a=-3, b=2b=2. The set is (−3,2)={x∈R:−3<x<2}(-3,2)=\{x\in\mathbb{R}: -3<x<2\}.
  2. Since the inequality uses strict << at both ends, −3-3 and 22 are both excluded from the set.
  3. On the number line: draw a horizontal line, mark the points −3-3 and 22; place an open (hollow) circle at −3-3 and an open (hollow) circle at 22 (indicating both are excluded), and draw the segment joining them to represent every real number strictly in between.
  4. Self-check: an interior point, e.g. x=0x=0, satisfies −3<0<2-3<0<2 ✓; the endpoint x=−3x=-3 fails −3<−3-3<-3 (false), and x=2x=2 fails 2<22<2 (false) — confirming both must be open circles, not filled.
✓Final answer

Segment from −3-3 to 22 with open/hollow circles at both −3-3 and 22 (both endpoints excluded).

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