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Exercise 7.3 · Q5

Q.A couple wishes to purchase a house for ₹12,00,000 with a down payment of ₹2,50,000. If they can amortize the balance at 9% per annum compounded monthly for 20 years

(i) What is their monthly payment
(ii) What is the total interest paid? (Given a240‾∣0.0075=111.1449a_{\overline{240}|0.0075} = 111.1449)
Andaman Nicobar CbseNCERTSubjective· 3mImportance★★★★★
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The couple borrows ₹9,50,000 at 9% p.a. compounded monthly for 20 years. Using the present value of an annuity formula, the monthly payment is ₹8,547.50 and the total interest paid over the loan term is ₹11,01,400.

The core idea here is present value of an annuity — specifically, a loan amortised with equal monthly payments. When you take a loan, the bank essentially buys an annuity from you: you promise to pay a fixed amount each month, and the bank gives you the lump sum today. The lump sum (the loan principal) must equal the present value of all those future payments, discounted at the loan's interest rate.

The loan balance is the house price minus the down payment:

₹12,00,000 − ₹2,50,000 = ₹9,50,000.

The interest is 9% per annum compounded monthly, so the monthly rate is

i=9%12=0.75%=0.0075i = \frac{9\%}{12} = 0.75\% = 0.0075.

The loan term is 20 years, which is 20×12=24020 \times 12 = 240 months.

We need the monthly payment RR such that the present value of 240 payments of RR at 0.75% per month equals ₹9,50,000.

Present value of an ordinary annuity:

PV=R×an‾∣i=R×1−(1+i)−niPV = R \times a_{\overline{n}|i} = R \times \frac{1 - (1+i)^{-n}}{i}

Here, PV=9,50,000PV = 9,50,000, n=240n = 240, i=0.0075i = 0.0075, and the problem gives a240‾∣0.0075=111.1449a_{\overline{240}|0.0075} = 111.1449.

  1. Set up the equation

9,50,000=R×111.14499,50,000 = R \times 111.1449

  1. Solve for the monthly payment

R=9,50,000111.1449R = \frac{9,50,000}{111.1449}

Doing the division:

R=8,547.50 (rounded to the nearest paisa)R = 8,547.50 \text{ (rounded to the nearest paisa)} …

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