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Q.Explain the hybridization involved in PCl5 molecule.

Andhra Pradesh BieapBIEAP Intermediate Board (1st Year) 2022Subjective· 4mImportance★★★★★
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Phosphorus in PCl5 is sp3d hybridised, giving a trigonal bipyramidal shape with three equatorial and two axial P-Cl bonds.

Phosphorus (Z = 15) has the ground state configuration 3s2 3p3. In the excited state, one 3s electron is promoted to a 3d orbital, giving five unpaired electrons: 3s1 3p3 3d1.

These five orbitals (one s, three p and one d) mix to form five equivalent sp3d hybrid orbitals. Each hybrid orbital overlaps with a singly occupied 3p orbital of a chlorine atom to form five P-Cl sigma bonds.

Geometry: The five sp3d orbitals point towards the corners of a trigonal bipyramid.

  • Three P-Cl bonds lie in the equatorial plane, at 120 degrees to one another.
  • Two P-Cl bonds are axial, perpendicular (90 degrees) to the equatorial plane. …

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