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Q.

Three boxes numbered I, II, III contain the balls as follows:

BoxWhiteBlackRed
I123
II211
III453

One box is randomly selected and a ball is drawn from it. If the ball is red, then find the probability that it is from box II.

Andhra Pradesh BieapBIEAP Intermediate Board 2025Subjective· 7mImportance★★★★★
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Use Bayes' theorem: find P(Red)P(\text{Red}) by totalling over the three equally-likely boxes, then take the box-II share of that total.

Box totals and red-ball counts:

BoxWhiteBlackRedTotal
I1236
II2114
III45312

Each box is equally likely to be selected: P(I)=P(II)=P(III)=13P(\text{I})=P(\text{II})=P(\text{III})=\dfrac13.

Conditional probabilities of drawing red from each box:

P(Red∣I)=36=12,P(Red∣II)=14,P(Red∣III)=312=14.P(\text{Red}\mid\text{I})=\frac36=\frac12,\quad P(\text{Red}\mid\text{II})=\frac14,\quad P(\text{Red}\mid\text{III})=\frac{3}{12}=\frac14.

By the law of total probability:

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