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Q.Two groups are competing for the position of the board of directors of a corporation. The probabilities that the first and the second groups will win are 0.6 and 0.4 respectively. Further, if the first group wins, the probability of introducing a new product is 0.7 and the corresponding probability is 0.3 if the second group wins. Then find the probability that the new product introduced was by the second group.

Odisha ChseOdisha CHSE +2 Science Board Exam 2026Subjective· 5mImportance★★★★★
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Applying Bayes' theorem with the given prior and conditional probabilities gives P(E2∣A)=29P(E_2\mid A)=\dfrac{2}{9}.

Let:

  • E1E_1 = event that group 1 wins, P(E1)=0.6P(E_1)=0.6
  • E2E_2 = event that group 2 wins, P(E2)=0.4P(E_2)=0.4
  • AA = event that the new product is introduced

Given: P(A∣E1)=0.7P(A\mid E_1)=0.7, P(A∣E2)=0.3P(A\mid E_2)=0.3.

We want P(E2∣A)P(E_2\mid A), the probability that group 2 was responsible given that the new product was introduced — this calls for Bayes' theorem:

P(E2∣A)=P(E2) P(A∣E2)P(E1) P(A∣E1)+P(E2) P(A∣E2)P(E_2\mid A)=\frac{P(E_2)\,P(A\mid E_2)}{P(E_1)\,P(A\mid E_1)+P(E_2)\,P(A\mid E_2)}

Numerator:

P(E2)P(A∣E2)=0.4×0.3=0.12P(E_2)P(A\mid E_2)=0.4\times0.3=0.12

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