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NCERT Exemplar · Q20

Q.The vectors a⃗=3i^−2j^+2k^\vec{a}=3\hat{i}-2\hat{j}+2\hat{k} and b⃗=−i^−2k^\vec{b}=-\hat{i}-2\hat{k} are the adjacent sides of a parallelogram. The acute angle between its diagonals is ________.

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The diagonals are a⃗+b⃗=2i^−2j^\vec{a}+\vec{b}=2\hat{i}-2\hat{j} and a⃗−b⃗=4i^−2j^+4k^\vec{a}-\vec{b}=4\hat{i}-2\hat{j}+4\hat{k}; their dot product gives cos⁡θ=12\cos\theta=\frac{1}{\sqrt{2}}, so the acute angle is 45∘45^\circ.

Setup

For a parallelogram with adjacent sides a⃗\vec{a} and b⃗\vec{b}, the two diagonals are the sum and difference of the sides:

d⃗1=a⃗+b⃗,d⃗2=a⃗−b⃗.\vec{d}_1=\vec{a}+\vec{b},\qquad \vec{d}_2=\vec{a}-\vec{b}.

Form the diagonals

With a⃗=3i^−2j^+2k^\vec{a}=3\hat{i}-2\hat{j}+2\hat{k} and b⃗=−i^+0j^−2k^\vec{b}=-\hat{i}+0\hat{j}-2\hat{k}:

d⃗1=(3−1)i^+(−2+0)j^+(2−2)k^=2i^−2j^,\vec{d}_1=(3-1)\hat{i}+(-2+0)\hat{j}+(2-2)\hat{k}=2\hat{i}-2\hat{j},

d⃗2=(3+1)i^+(−2−0)j^+(2+2)k^=4i^−2j^+4k^.\vec{d}_2=(3+1)\hat{i}+(-2-0)\hat{j}+(2+2)\hat{k}=4\hat{i}-2\hat{j}+4\hat{k}.

Dot product and magnitudes

d⃗1⋅d⃗2=(2)(4)+(−2)(−2)+(0)(4)=8+4+0=12,\vec{d}_1\cdot\vec{d}_2=(2)(4)+(-2)(-2)+(0)(4)=8+4+0=12,

∣d⃗1∣=22+(−2)2+02=8=22,|\vec{d}_1|=\sqrt{2^2+(-2)^2+0^2}=\sqrt{8}=2\sqrt{2},

∣d⃗2∣=42+(−2)2+42=16+4+16=36=6.|\vec{d}_2|=\sqrt{4^2+(-2)^2+4^2}=\sqrt{16+4+16}=\sqrt{36}=6. …

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