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Worked Examples · Example 3

Q.Find the mean deviation about the median for the following data: 3, 9, 5, 3, 12, 10, 18, 4, 7, 19, 21.

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Arranged in order, the median of the 1111 values is 99, and the mean deviation about the median is 5811≈5.27\dfrac{58}{11} \approx 5.27.

Understanding Mean Deviation About the Median

The median is the middle value that splits ordered data into two equal halves. Mean deviation about the median reports the average absolute distance of each observation from that middle value.

M.D.(M)=∑∣xi−M∣n\text{M.D.}(M) = \frac{\sum |x_i - M|}{n}

Step-by-Step Solution

1. Arrange the data in ascending order

3, 3, 4, 5, 7, 9, 10, 12, 18, 19, 213,\ 3,\ 4,\ 5,\ 7,\ 9,\ 10,\ 12,\ 18,\ 19,\ 21

There are n=11n = 11 observations (odd).

2. Find the median

For odd nn, the median is the (n+12)th\left(\dfrac{n+1}{2}\right)^{\text{th}} value =6th= 6^{\text{th}} value =9= 9.

3. Absolute deviations from the median

| xix_i | ∣xi−9∣|x_i - 9| |

|-------|-------------| …

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