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Q.What is mutual inductance? S1 and S2 are two long coaxial solenoids of radii r1 and r2, where r1 ≪ r2. S1 and S2 have equal lengths l. If n1 and n2 be the number of turns/length and I2 be the current flowing through S2, find an expression for mutual inductance M12 of S1 with respect to S2. OR Two concentric coils having radii r1 and r2 are placed coaxially, where r1 ≪ r2. Obtain an expression for mutual inductance M12 of the inner coil with respect to the outer coil. Define self-inductance.

Assam AhsecAHSEC Higher Secondary (HS) Final Examination 2022Subjective· 3mImportance★★★★★
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Mutual inductance is the coefficient linking the flux linked with one coil to the current in a neighbouring coil. For coaxial solenoids, M₁₂ = μ₀n₁n₂πr₁²l; for concentric coils, M₁₂ = μ₀πr₁²N₁N₂/(2r₂).

Main part — coaxial solenoids:

Mutual inductance M₁₂ of a coil (1) with respect to another coil (2) is defined by Φ₁ = M₁₂ I₂, i.e. it is the flux linked with coil 1 per unit current in coil 2 (equivalently the induced emf in 1 per unit rate of change of current in 2).

S1 (radius r1) is inside S2 (radius r2), r1 ≪ r2, both of length l, with n1 and n2 turns per unit length respectively. When current I2 flows in the outer solenoid S2, it produces a (nearly) uniform field inside itself: B2 = μ0 n2 I2.

Since S1 lies entirely within S2 (r1 ≪ r2), essentially all of this field also threads through S1. Flux linked with S1 (which has n1 l turns in all):

Φ1 = (n1 l) × B2 × (π r1²) = μ0 n1 n2 I2 π r1² l.

Mutual inductance: M12 = Φ1/I2 = μ0 n1 n2 π r1² l.

OR — concentric circular coils:

Two concentric, coplanar circular coils of radii r1 ≪ r2 (say N1 turns on the inner coil, N2 turns on the outer coil). Current I2 in the outer coil produces, at its centre, a field B2 = μ0 N2 I2/(2r2). Since r1 ≪ r2, this field is essentially uniform over the small inner coil's area.

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