Q.Which of the following is not paramagnetic?
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Molecular Orbital Theory — MO Diagrams, Bond Order & Magnetism
The big idea. When atoms bond, their atomic orbitals combine (LCAO) into molecular orbitals that belong to the whole molecule. Each pair of atomic orbitals gives one bonding MO (lower energy, electron density between the nuclei) and one antibonding MO (higher energy, marked with a *). Fill these with the molecule's electrons, and you can read off its bond order, stability and — crucially — its magnetism.
The two orderings
For second-period homonuclear diatomics there are two energy orderings, because s–p mixing pushes the σ2p up:
- Li₂ through N₂ (≤ 14 valence e⁻) — s–p mixing order: σ2s, σ2s, (π2px = π2py), σ2pz, (π2px = π2py), σ2pz. Here the π2p bonding MOs sit below σ2pz.
- O₂, F₂, Ne₂ — normal order: σ2s, σ2s, σ2pz, (π2px = π2py), (π2px = π2py), σ2pz. Here σ2pz sits below the π2p.
Bond order
Bond order = ½ (N_bonding − N_antibonding).
Fill the MOs (Aufbau, Pauli, Hund) and count. Standard values:
| Species | e⁻ | Bond order | Unpaired e⁻ | Magnetism |
|---|---|---|---|---|
| H₂ | 2 | 1 | 0 | diamagnetic |
| He₂ | 4 | 0 | — | does not exist |
| Li₂ | 6 | 1 | 0 | diamagnetic |
| B₂ | 10 | 1 | 2 | paramagnetic |
| C₂ | 12 | 2 | 0 | diamagnetic |
| N₂ | 14 | 3 | 0 | diamagnetic |
| O₂ | 16 | 2 | 2 | paramagnetic |
| F₂ | 18 | 1 | 0 | diamagnetic |
Ions follow from adding/removing electrons: O₂⁺ 2.5, O₂⁻ (superoxide) 1.5, O₂²⁻ (peroxide) 1; N₂⁺ and N₂⁻ both 2.5; He₂⁺ 0.5; NO 2.5, NO⁺ 3, CN⁻ 3, CO 3.
Magnetism — MOT's triumph
A species is paramagnetic if it has unpaired electrons, diamagnetic if all are paired. MOT famously predicts that O₂ is paramagnetic — its last two electrons go singly into the degenerate π*2p orbitals (Hund's rule) — which the simple Lewis structure O=O cannot explain. B₂ is also paramagnetic (two electrons singly in π2p).
Bond order, length, energy — and adding/removing an electron
Higher bond order means a shorter bond and a higher dissociation energy. Whether ionisation raises or lowers the bond order depends on which MO the electron leaves or enters:
- O₂ → O₂⁺ removes an antibonding π* electron → bond order rises (2 → 2.5).
- O₂ → O₂⁻ adds an antibonding π* electron → bond order falls (2 → 1.5). …
A species is paramagnetic if its molecular-orbital configuration has one or more unpaired electrons. …
CO is the only one of the four species that is NOT paramagnetic — it is diamagnetic.
Using molecular orbital theory:
- N2+ (13 electrons, isoelectronic-type with an odd electron count) has 1 unpaired electron — paramagnetic.
- CO (14 electrons, isoelectronic with N2) has a fully-paired MO configuration — diamagnetic. …
- CBSE 2025Set ANNUAL1 markMCQQ.Which of the following is not paramagnetic?(a) N2+(b) CO(c) O2-(d) NO
›Reveal solutionSolution
CO is the only one of the four species that is NOT paramagnetic — it is diamagnetic.
Using molecular orbital theory:
- N2+ (13 electrons, isoelectronic-type with an odd electron count) has 1 unpaired electron — paramagnetic.
- CO (14 electrons, isoelectronic with N2) has a fully-paired MO configuration — diamagnetic. …
- CBSE 2024Set ANNUAL1 markMCQQ.The number of unpaired electrons in liquid oxygen molecule is(a) 1(b) 2(c) 3(d) 4
›Reveal solutionSolution
O2 has 2 unpaired electrons (in the π2px and π2py antibonding orbitals), explaining its paramagnetism (visible in liquid O2 being attracted to a magnet).
By molecular orbital theory, the electronic configuration of O2 is:
σ1s2σ1s∗2σ2s2σ2s∗2σ2pz2π2px2π2py2π2px∗1π2py∗1
…
- CBSE 2023Set ANNUAL1 markMCQQ.Assertion : Oxygen molecule is Paramagnetic. Reason : It has two unpaired electrons in its bonding molecular orbital.(a) Assertion is true but reason is false.(b) Both assertion and reason are true and reason is the correct explanation of assertion.(c) Both assertion and reason are false.(d) Both assertion and reason are true but reason is not the correct explanation of assertion.
›Reveal solutionSolution
Oxygen is genuinely paramagnetic (assertion true), but its two unpaired electrons sit in the antibonding pi*2p molecular orbitals, not the bonding ones -- so the reason, as worded, is false.
By molecular orbital theory, the electronic configuration of O2 (16 electrons total) is:
sigma1s2 sigma1s2 sigma2s2 sigma2s2 sigma2pz2 pi2px2 pi2py2 pi2px1 pi2py1
The last two electrons singly occupy the two degenerate antibonding pi* molecular orbitals (pi2px and pi2py), each with one unpaired electron (following Hund's rule). This gives O2 a net of two unpaired electrons, which is exactly why it is paramagnetic (attracted into a magnetic field) -- a result MO theory correctly predicts, unlike simple Lewis/valence-bond structures which show all electrons paired …
- CBSE 2022Set ANNUAL1 markMCQQ.Which one of the following is diamagnetic?(a) O2 2- (superoxide/peroxide ion)(b) O2 + (dioxygenyl cation)(c) O2 (dioxygen)(d) None of these
›Reveal solutionSolution
Molecular orbital theory shows O2 and O2+ both have unpaired electrons in their pi* antibonding orbitals (paramagnetic), while O2^2- (peroxide, 18 valence-region electrons) has those pi* orbitals completely filled, leaving no unpaired electrons — so it is diamagnetic.
Building the molecular orbital electron configuration for the O2 family (order: sigma2s, sigma2s, sigma2pz, pi2px = pi2py, pi2px = pi2py, sigma2pz):
O2 (16 electrons): (sigma2s)2 (sigma2s)2 (sigma2pz)2 (pi2px)2(pi2py)2 (pi2px)1(pi2py)1 (sigma2pz)0
→ 2 unpaired electrons in the two pi* orbitals → PARAMAGNETIC.
O2+ (15 electrons, one less than O2): removes one electron from a pi* orbital → (pi2px)1(pi2py)0
→ 1 unpaired electron → PARAMAGNETIC.
…
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