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Q.Draw the molecular orbital diagram for O2 molecule. Write its molecular orbital electronic configuration and predict its magnetic behaviour.

Jammu Kashmir JkboseJammu and Kashmir Board of School Education (Class 11) 2024Subjective· 3mImportance★★★★★
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Figure — Molecular-orbital energy-level diagram of O2 (16 electrons). Left and right columns are the 2s/2p at
Figure — Molecular-orbital energy-level diagram of O2 (16 electrons). Left and right columns are the 2s/2p at

O2 has 16 electrons total; its MO filling places one electron each in the two degenerate pi*2p orbitals, giving bond order 2 and explaining why oxygen is paramagnetic.

Oxygen molecule, O2, has a total of 16 electrons (8 from each O atom). According to molecular orbital theory, these are filled into molecular orbitals in increasing order of energy:

sigma1s2, sigma1s2 (these two, from the 1s core electrons, are usually abbreviated 'KK' and not involved in bonding), then: sigma2s2, sigma2s2, sigma2pz2, pi2px2 = pi2py2, pi2px1 = pi2py1

Molecular orbital electronic configuration of O2:

KK, sigma2s2, sigma2s2, sigma2pz2, (pi2px2 = pi2py2), (pi2px1 = pi*2py1)

By Hund's rule, the two electrons remaining after filling the bonding pi2p orbitals go into the two degenerate antibonding pi2p orbitals (pi2px and pi*2py) singly, with parallel spins, rather than pairing up in just one of them.

Bond order = 1/2 x (electrons in bonding MOs - electrons in antibonding MOs)

Bonding electrons (excluding the K-shell sigma1s/sigma1s which cancel): sigma2s2 + sigma2pz2 + pi2px2 + pi2py2 = 2+2+2+2 = 8 Antibonding electrons: sigma2s2 + pi2px1 + pi2py1 = 2+1+1 = 4 …

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