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NCERT Exemplar · Q30

Q.If cc is r.m.s. speed of molecules in a gas and vv is the speed of sound waves in the gas, show that c/vc/v is constant and independent of temperature for all diatomic gases.

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The ratio c/vc/v depends only on the adiabatic index γ\gamma, which is fixed at 7/57/5 for all diatomic gases. Since temperature cancels out when forming the ratio, c/v=3/γ=15/7c/v = \sqrt{3/\gamma} = \sqrt{15/7} remains constant for all diatomic molecules.

The question asks us to prove something beautiful: that the ratio of molecular speed to sound speed is a universal constant for an entire class of gases. This universality emerges because both speeds scale with temperature in exactly the same way, leaving behind only the intrinsic structure of the molecule.

Why this ratio matters

The r.m.s. speed cc measures how fast individual molecules dart around in thermal motion. The sound speed vv measures how quickly a pressure disturbance propagates through the gas as a collective wave. Both depend on temperature, but their ratio reveals something about the gas's internal degrees of freedom—information encoded in γ\gamma, the ratio of specific heats.

Step-by-step demonstration

1. Write the r.m.s. speed from kinetic theory

The root-mean-square speed of molecules comes directly from the equipartition theorem applied to translational kinetic energy:

c=3RTMc = \sqrt{\frac{3RT}{M}}

where RR is the universal gas constant, TT the absolute temperature, and MM the molar mass.

2. Write the speed of sound in the gas

Sound waves in a gas are adiabatic compressions and rarefactions. The Newton-Laplace formula gives:

v=γRTMv = \sqrt{\frac{\gamma RT}{M}}

where γ=Cp/Cv\gamma = C_p/C_v is the adiabatic index (ratio of specific heats at constant pressure and volume).

3. Form the ratio

Dividing the two expressions:

cv=3RTMγRTM=3RT/MγRT/M=3γ\frac{c}{v} = \frac{\sqrt{\frac{3RT}{M}}}{\sqrt{\frac{\gamma RT}{M}}} = \sqrt{\frac{3RT/M}{\gamma RT/M}} = \sqrt{\frac{3}{\gamma}}

Notice that RR, TT, and MM all cancel. The ratio depends only on γ\gamma.

cv=3γ\frac{c}{v} = \sqrt{\frac{3}{\gamma}}

4. Evaluate for diatomic gases

For a diatomic gas at ordinary temperatures (where rotational modes are active but vibrational modes are frozen), the degrees of freedom are:

  • 3 translational
  • 2 rotational
  • Total: 5 active degrees of freedom

This gives:

Cv=52R,Cp=Cv+R=72RC_v = \frac{5}{2}R, \quad C_p = C_v + R = \frac{7}{2}R …

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