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Q.What do you mean by half-life and average life of a radioactive substance? Establish disintegration formula (N = N₀ e^(−λt)) for radioactive substance.

Bihar BsebBihar Board Intermediate 2021Subjective· 5mImportance★★★★★
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Half-life = time to decay to N₀/2; mean life = 1/λ. Integrating dN/dt=−λNdN/dt=-\lambda N gives N=N0e−λtN=N_0e^{-\lambda t}, and T1/2=0.693 τT_{1/2}=0.693\,\tau.

Half-life (T1/2T_{1/2}): The half-life of a radioactive substance is the time in which half of the original number of undecayed nuclei disintegrate (i.e. N=N0/2N = N_0/2).

Average (mean) life (τ\tau): The average life is the mean of the lifetimes of all the nuclei; it equals the reciprocal of the decay constant, τ=1/λ\tau = 1/\lambda.

Derivation of the disintegration (decay) law.

According to the law of radioactive decay, the rate of disintegration at any instant is proportional to the number of undecayed nuclei NN present:

dNdt=−λN\frac{dN}{dt} = -\lambda N

where λ\lambda is the decay constant and the minus sign shows NN decreases with time. Rearranging and integrating:

dNN=−λ dt\frac{dN}{N} = -\lambda\,dt

∫N0NdNN=−λ∫0tdt\int_{N_0}^{N}\frac{dN}{N} = -\lambda\int_0^t dt

ln⁡N−ln⁡N0=−λt ⇒ ln⁡NN0=−λt\ln N - \ln N_0 = -\lambda t \ \Rightarrow\ \ln\frac{N}{N_0} = -\lambda t

N=N0 e−λt\boxed{N = N_0\,e^{-\lambda t}}

where N0N_0 is the number of nuclei at t=0t = 0 and NN the number remaining at time tt. Thus the number of undecayed nuclei falls exponentially with time.

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