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Q.What are 'Energy Bands'? How are these formed? Distinguish between Conductors, Semiconductors and Insulators on the basis of Formation of these bands. (1½ +2+1½ = 5)

Bihar BsebBihar Board Intermediate 2018Subjective· 5mImportance★★★★★
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Atomic levels split into closely-spaced energy bands in solids; the size of the forbidden gap between the valence and conduction bands distinguishes conductors, semiconductors and insulators. [OR: β⁺-decay Q ≈ 0.96 MeV, matching the 0.960 MeV maximum positron energy.]

Difference between energy bands metals insulators
Difference between energy bands metals insulators

Energy bands: In an isolated atom electrons occupy discrete energy levels. When N atoms come together to form a solid, the atoms are so close that their electron wavefunctions overlap. By the Pauli exclusion principle each discrete level must split into N closely spaced sub-levels. As N is enormous, these sub-levels merge into essentially continuous ranges of allowed energy called energy bands, separated by forbidden gaps.

How they form: The highest band completely filled at 0 K is the valence band; the next higher (largely empty) band is the conduction band; between them lies the forbidden energy gap E_g. Only electrons in the conduction band (or in a partly filled band) can conduct electricity.

Distinction on the basis of band formation:

  • Conductors (metals): the valence and conduction bands overlap, or the conduction band is partly filled, so E_g ≈ 0. Plenty of free electrons are always available → high conductivity.
  • Semiconductors: a small forbidden gap, E_g ≈ 1 eV (Si ≈ 1.1 eV, Ge ≈ 0.7 eV). At 0 K they behave like insulators, but at room temperature some electrons are thermally excited across the gap → moderate, temperature-sensitive conductivity.
  • Insulators: a large forbidden gap, E_g > 3 eV (e.g. diamond ≈ 6 eV). Electrons cannot be excited across it under ordinary conditions → practically no conduction.

OR (nuclear Q-value): For β⁺ (positron) emission 611C→511B+e++ν^{11}_6\text{C} \to {}^{11}_5\text{B} + e^+ + \nu, using atomic masses the Q-value is

Q=[m(11C)−m(11B)−2me]c2.Q = \big[m(^{11}\text{C}) - m(^{11}\text{B}) - 2m_e\big]c^2.

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