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Worked Examples · Example 7

Q.The difference between the Compound Interest (CI) and Simple Interest (SI) on a certain sum of money at 40% per annum for 2 years is ₹500. Find the sum.

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Use the standard identity for the 2-year CI–SI difference to solve directly for the principal.

For 2 years, CI−SI=P(R100)2CI-SI=P\left(\dfrac{R}{100}\right)^2, where PP = sum (principal), RR = rate per annum (%).

Given: R=40%R=40\% per annum, T=2T=2 years, CI−SI=₹500CI-SI=₹500.

  1. Write the identity:

CI−SI=P(R100)2CI-SI=P\left(\dfrac{R}{100}\right)^2

  1. Substitute R=40R=40 and the given difference:

500=P(40100)2=P(0.4)2=0.16P500=P\left(\dfrac{40}{100}\right)^2=P(0.4)^2=0.16P

  1. Solve for PP: …

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