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Exercise 2.2 · Q2

Q.Find the total number of days from 26th January 2008 to 15 May 2008?

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Adding the remaining days of January, all of Feb–Apr (2008 is a leap year), and the days into May gives 110110 days.

Number of days between two dates == (days remaining in the start month after the start date) ++ (full days in every month fully spanned) ++ (day-of-month of the end date). A year is a leap year if divisible by 4 (and, for century years, by 400); 2008÷4=5022008\div4=502, so 2008 is a leap year and February has 2929 days.

Given: start date =26=26 January 2008, end date =15=15 May 2008.

  1. Days left in January after the 26th: 31−26=531-26=5 (the 27th through the 31st).
  2. Full month of February (leap year): 2929 days.
  3. Full month of March: 3131 days.
  4. Full month of April: 3030 days.
  5. Days elapsed in May up to the 15th: 1515 days.
  6. Sum all parts:

5+29+31+30+15=1105+29+31+30+15 = 110

  1. Self-check: running total — after Jan: 5; after Feb: 5+29=345+29=34; after Mar: 34+31=6534+31=65; after Apr: 65+30=9565+30=95; after May 15: 95+15=11095+15=110. ✓
✓Final answer

The total number of days from 26th January 2008 to 15th May 2008 is 110 days.

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