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Worked Examples · Example 36

Q.A pendulum swings through an arc of 25 cm. On each successive swing, the pendulum covers an arc equal to 90% of the previous swing. Find the length of the arc on the sixth swing and the total distance the pendulum travels before coming to rest.

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Each swing's arc is 90%90\% of the previous one, so the arc lengths form a geometric progression; the 6th6^{\text{th}} term gives the sixth-swing arc, and the infinite sum gives the total distance before the pendulum stops.

For a GP with first term aa and common ratio rr:

nth term: an=arn−1,Sum to infinity (∣r∣<1):S∞=a1−rn\text{th term: } a_n = ar^{n-1}, \qquad \text{Sum to infinity }(|r|<1): S_\infty = \frac{a}{1-r}

  1. Identify the GP: first swing arc a=25a = 25 cm; each successive swing is 90%90\% of the previous, so common ratio r=0.9r = 0.9.
  2. Arc on the 6th6^{\text{th}} swing uses a6=ar6−1=ar5a_6 = ar^{6-1} = ar^5:

a6=25×(0.9)5a_6 = 25 \times (0.9)^5

  1. Compute (0.9)5(0.9)^5 step by step: (0.9)2=0.81(0.9)^2=0.81, (0.9)3=0.729(0.9)^3=0.729, (0.9)4=0.6561(0.9)^4 = 0.6561, (0.9)5=0.59049(0.9)^5 = 0.59049.
  2. a6=25×0.59049=14.76225≈14.76 cma_6 = 25 \times 0.59049 = 14.76225 \approx 14.76 \text{ cm}
  3. Total distance travelled before the pendulum comes to rest is the sum of ALL swing arcs, out to infinity (since r=0.9r=0.9, ∣r∣<1|r|<1, the series converges): …

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