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Exercise 5.2 · Q5

Q.The sum of the first two terms of a G.P. is 36 and the product of the first term and third term is 9 times the second term. Find the sum of the first 8 terms.

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Use the two given conditions to find aa and rr, then apply the G.P. sum formula for 8 terms.

G.P. with first term aa, common ratio rr: nnth term =arn−1=ar^{n-1}; sum of nn terms Sn=a(1−rn)1−rS_n=\dfrac{a(1-r^n)}{1-r} (r≠1r\neq1).

  1. Let the G.P. have first term aa and common ratio rr; terms are a,ar,ar2,…a,ar,ar^2,\ldots
  2. Sum of first two terms: a+ar=36a+ar=36.
  3. Product of first and third term equals 9 times the second term: a⋅ar2=9(ar)a\cdot ar^2=9(ar), i.e. a2r2=9ara^2r^2=9ar.
  4. Dividing by arar (nonzero): ar=9ar=9.
  5. From step 2: a=36−ar=36−9=27a=36-ar=36-9=27.
  6. So r=9a=927=13r=\dfrac{9}{a}=\dfrac{9}{27}=\dfrac13.
  7. Sum of first 8 terms: S8=27(1−(1/3)8)1−1/3=27(1−16561)2/3=27×32×65606561S_8=\dfrac{27\left(1-(1/3)^8\right)}{1-1/3}=\dfrac{27\left(1-\frac{1}{6561}\right)}{2/3}=27\times\dfrac32\times\dfrac{6560}{6561}. …

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