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Exercise 3.4 · Q1

Q.In a group of 70 people, 37 like coffee, 52 like tea and each person likes atleast one of the two drinks. How many people like both coffee and tea.

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Since every person likes at least one drink, the union of the coffee-lovers and tea-lovers sets equals the whole group; the inclusion-exclusion formula then gives the overlap.

Inclusion–exclusion for two sets: n(C∪T)=n(C)+n(T)−n(C∩T)n(C\cup T) = n(C) + n(T) - n(C\cap T).

  1. Given: total people n(C∪T)=70n(C\cup T) = 70 (everyone likes at least one drink), n(C)=37n(C) = 37 (coffee), n(T)=52n(T) = 52 (tea).

  2. Apply the formula: n(C∪T)=n(C)+n(T)−n(C∩T)n(C\cup T) = n(C) + n(T) - n(C\cap T).

    70=37+52−n(C∩T)70 = 37 + 52 - n(C\cap T)

  3. Simplify the right side: 37+52=8937 + 52 = 89, so 70=89−n(C∩T)70 = 89 - n(C\cap T).

  4. Solve for the overlap: n(C∩T)=89−70=19n(C\cap T) = 89 - 70 = 19.

  5. Check: coffee-only =37−19=18= 37-19=18; tea-only =52−19=33=52-19=33; both =19=19; total =18+33+19=70=18+33+19=70. ✓ Matches the group size.

✓Final answer

19 people like both coffee and tea.

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