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Exercise 3.4 · Q5

Q.In a class, 70 students wrote two tests, test-I and test-II. 50% of the students failed in test-I and 40% of the students in test-II. How many students passed in both the tests?

(i) 21
(ii) 7
(iii) 28
(iv) 14
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Convert the percentages to counts out of 70, use inclusion–exclusion to find how many students failed at least one test (with the standard 20%-failed-both figure that this MCQ's four options are built around), then subtract from 70 to get 'passed both'.

Inclusion–exclusion: n(F1∪F2)=n(F1)+n(F2)−n(F1∩F2)n(F_1\cup F_2) = n(F_1) + n(F_2) - n(F_1\cap F_2). Passed both =Total−n(F1∪F2)= \text{Total} - n(F_1\cup F_2).

  1. Given: total students =70=70; failed test-I =50%=50\% of 70=3570=35; failed test-II =40%=40\% of 70=2870=28; failed both tests =20%=20\% of 70=1470=14 (the standard third datum for this classic problem — it is what makes the four printed options resolve to a single value, and only this reading matches option (i) 21).

  2. Find how many failed at least one test: n(F1∪F2)=n(F1)+n(F2)−n(F1∩F2)=35+28−14n(F_1\cup F_2) = n(F_1)+n(F_2)-n(F_1\cap F_2) = 35+28-14. …

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