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Exercises · 9.7

Q.Propanal and pentan-3-one are the ozonolysis products of an alkene? What is the structural formula of the alkene?

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The alkene must have a carbon‑carbon double bond that, when cleaved by ozone, gives exactly propanal (CH3CH2CHO\mathrm{CH_3CH_2CHO}) and pentan‑3‑one (CH3CH2COCH2CH3\mathrm{CH_3CH_2COCH_2CH_3}). Reconnecting the two carbonyl fragments across the original double bond yields 3‑ethylhex‑3‑ene.


Why this approach works

Ozonolysis is a clean chemical “scissors” that cuts a C=C\mathrm{C=C} bond and replaces each carbon of the double bond with a carbonyl group (C=O\mathrm{C=O}).

  • If the carbon had two hydrogens attached, you get an aldehyde (−CHO\mathrm{-CHO}).
  • If it had one hydrogen and one alkyl group, you still get an aldehyde.
  • If it had two alkyl groups (no hydrogen), you get a ketone (C=O\mathrm{C=O} with two R\mathrm{R} groups).

So the two products tell us exactly what was attached to each end of the original double bond. To find the alkene, we simply “glue” the two carbonyl fragments back together — removing the oxygen atoms and joining the two carbons with a double bond.


Step‑by‑step reconstruction

  1. Identify the carbonyl fragments

    • Propanal: CH3CH2CHO\mathrm{CH_3CH_2CHO} The aldehyde carbon (the C=O\mathrm{C=O}) came from a carbon that had one hydrogen and one alkyl group (CH3CH2−\mathrm{CH_3CH_2-}) attached to the original double bond.
    • Pentan‑3‑one: CH3CH2COCH2CH3\mathrm{CH_3CH_2COCH_2CH_3} The ketone carbon (the C=O\mathrm{C=O}) came from a carbon that had two alkyl groups (CH3CH2−\mathrm{CH_3CH_2-} and CH3CH2−\mathrm{CH_3CH_2-}) attached to the original double bond — no hydrogen.
  2. Reconnect the two carbons

    Remove the oxygen from each carbonyl and join the two carbons with a double bond.

    • Left fragment (from propanal): CH3CH2CH=\mathrm{CH_3CH_2CH=}
    • Right fragment (from pentan‑3‑one): =C(CH2CH3)2\mathrm{=C(CH_2CH_3)_2}

    Putting them together:

CH3CH2CH=C(CH2CH3)2\mathrm{CH_3CH_2CH=C(CH_2CH_3)_2}

  1. Name the alkene The longest chain containing the double bond has 6 carbons: CH3CH2CH=C(CH2CH3)2\mathrm{CH_3CH_2CH=C(CH_2CH_3)_2} Number from the end nearer the double bond: …

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