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Worked Examples · Example 8.18

Q.Explain why the following two structures, I and II, cannot be the major contributors to the real structure of CH₃COOCH₃ (methyl acetate).

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The two structures the textbook prints for methyl acetate both involve charge separation, which costs energy and makes any contributor minor; structure I is doubly penalised because its central carbon is left with an incomplete octet (six electrons).

The major contributor for methyl acetate is the familiar neutral ester structure:

CH3−C(=O)−O−CH3CH_3-\text{C}(=\text{O})-\text{O}-CH_3

Every atom is neutral, the carbonyl carbon has four bonds (a full octet), and both oxygens keep two lone pairs. The question asks why the two charge-separated structures printed in the textbook cannot be major contributors.

Structure I: CH3−C+(−O−)−O−CH3CH_3-\overset{+}{\text{C}}(-\text{O}^-)-\text{O}-CH_3

The carbonyl π pair has moved entirely onto the top oxygen. Two things go wrong at once:

  1. Charge separation. A negative charge on the former carbonyl oxygen and a positive charge on carbon must be held apart against their attraction — that always raises the energy relative to the neutral structure.
  2. An incomplete octet on carbon. The central carbon now has just three σ bonds and no π bond — six valence electrons. A second-period atom with a sextet is a high-energy arrangement (it is essentially a carbocation centre).

Structure II: CH3−C(−O−)=O+−CH3CH_3-\text{C}(-\text{O}^-)=\overset{+}{\text{O}}-CH_3 …

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