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Worked Examples · Example 38

Q.Solve for xx, yy and zz: 2x−3y=52x - 3y = 5; 5x+3y=25x + 3y = 2.

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The two given equations involve only xx and yy; solving AX=BAX=B gives x=1, y=−1x=1,\ y=-1.

X=A−1BX=A^{-1}B; for 2×22\times2, A−1=1det⁡A[d−b−ca]A^{-1}=\dfrac{1}{\det A}\begin{bmatrix}d&-b\\-c&a\end{bmatrix}.

  1. Only two equations are given, so we solve for x,yx,y:

[2−353][xy]=[52].\begin{bmatrix} 2 & -3 \\ 5 & 3 \end{bmatrix}\begin{bmatrix} x \\ y \end{bmatrix} = \begin{bmatrix} 5 \\ 2 \end{bmatrix}.

  1. det⁡A=(2)(3)−(−3)(5)=6+15=21≠0\det A = (2)(3)-(-3)(5) = 6+15 = 21 \neq 0.

  2. Inverse:

    A−1=121[33−52].A^{-1} = \frac{1}{21}\begin{bmatrix} 3 & 3 \\ -5 & 2 \end{bmatrix}. …

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